(X-14)(x+10)=180

Solution for (X-14)(x+10)=180 equation:

(X-14)(X+10)=180

We move all terms to the left:

(X-14)(X+10)-(180)=0

We multiply parentheses ..

(+X^2+10X-14X-140)-180=0

We get rid of parentheses

X^2+10X-14X-140-180=0

We add all the numbers together, and all the variables

X^2-4X-320=0

a = 1; b = -4; c = -320;
Δ = b2-4ac
Δ = -42-4·1·(-320)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-36}{2*1}=\frac{-32}{2}
=-16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+36}{2*1}=\frac{40}{2}
=20
$