(X+4)(x-3)=72

Solution for (X+4)(x-3)=72 equation:

(X+4)(X-3)=72

We move all terms to the left:

(X+4)(X-3)-(72)=0

We multiply parentheses ..

(+X^2-3X+4X-12)-72=0

We get rid of parentheses

X^2-3X+4X-12-72=0

We add all the numbers together, and all the variables

X^2+X-84=0

a = 1; b = 1; c = -84;
Δ = b2-4ac
Δ = 12-4·1·(-84)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{337}}{2*1}=\frac{-1-\sqrt{337}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{337}}{2*1}=\frac{-1+\sqrt{337}}{2}
$