(X+4)(x-2)=x(x+3)-10

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Solution for (X+4)(x-2)=x(x+3)-10 equation: 



(X+4)(X-2)=X(X+3)-10

We move all terms to the left:

(X+4)(X-2)-(X(X+3)-10)=0

We multiply parentheses ..

(+X^2-2X+4X-8)-(X(X+3)-10)=0



We calculate terms in parentheses: -(X(X+3)-10), so:

X(X+3)-10

We multiply parentheses

X^2+3X-10

Back to the equation:

-(X^2+3X-10)



We get rid of parentheses

X^2-X^2-2X+4X-3X-8+10=0

We add all the numbers together, and all the variables

-1X+2=0

We move all terms containing X to the left, all other terms to the right

-X=-2

X=-2/-1

X=+2

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