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(X+4)(X+5)=76
We move all terms to the left:
(X+4)(X+5)-(76)=0
We multiply parentheses ..
(+X^2+5X+4X+20)-76=0
We get rid of parentheses
X^2+5X+4X+20-76=0
We add all the numbers together, and all the variables
X^2+9X-56=0
a = 1; b = 9; c = -56;
Δ = b2-4ac
Δ = 92-4·1·(-56)
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{305}}{2*1}=\frac{-9-\sqrt{305}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{305}}{2*1}=\frac{-9+\sqrt{305}}{2} $
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