(X+3)-2(3-5x)=4(x+5)-2

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Solution for (X+3)-2(3-5x)=4(x+5)-2 equation: 



(X+3)-2(3-5X)=4(X+5)-2

We move all terms to the left:

(X+3)-2(3-5X)-(4(X+5)-2)=0

We add all the numbers together, and all the variables

(X+3)-2(-5X+3)-(4(X+5)-2)=0

We multiply parentheses

(X+3)+10X-(4(X+5)-2)-6=0

We get rid of parentheses

X+10X-(4(X+5)-2)+3-6=0



We calculate terms in parentheses: -(4(X+5)-2), so:

4(X+5)-2

We multiply parentheses

4X+20-2

We add all the numbers together, and all the variables

4X+18

Back to the equation:

-(4X+18)



We add all the numbers together, and all the variables

11X-(4X+18)-3=0

We get rid of parentheses

11X-4X-18-3=0

We add all the numbers together, and all the variables

7X-21=0

We move all terms containing X to the left, all other terms to the right

7X=21

X=21/7

X=3

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