(X+3)*2x=x*7

Solution for (X+3)*2x=x*7 equation:

(X+3)*2X=X*7

We move all terms to the left:

(X+3)*2X-(X*7)=0

We add all the numbers together, and all the variables

(X+3)*2X-(+X*7)=0

We multiply parentheses

2X^2+6X-(+X*7)=0

We get rid of parentheses

2X^2+6X-X*7=0

Wy multiply elements

2X^2+6X-7X=0

We add all the numbers together, and all the variables

2X^2-1X=0

a = 2; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*2}=\frac{0}{4}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*2}=\frac{2}{4}
=1/2
$