(X+3)(x+3)=16+(x+1)(x-1)

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Solution for (X+3)(x+3)=16+(x+1)(x-1) equation: 



(X+3)(X+3)=16+(X+1)(X-1)

We move all terms to the left:

(X+3)(X+3)-(16+(X+1)(X-1))=0

We use the square of the difference formula

X^2+(X+3)(X+3)+1=0

We multiply parentheses ..

X^2+(+X^2+3X+3X+9)+1=0

We get rid of parentheses

X^2+X^2+3X+3X+9+1=0

We add all the numbers together, and all the variables

2X^2+6X+10=0

a = 2; b = 6; c = +10;
Δ = b2-4ac
Δ = 62-4·2·10
Δ = -44
Delta is less than zero, so there is no solution for the equation

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