(X+3)(4x+4)=0

Solution for (X+3)(4x+4)=0 equation:

(X+3)(4X+4)=0

We multiply parentheses ..

(+4X^2+4X+12X+12)=0

We get rid of parentheses

4X^2+4X+12X+12=0

We add all the numbers together, and all the variables

4X^2+16X+12=0

a = 4; b = 16; c = +12;
Δ = b2-4ac
Δ = 162-4·4·12
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8}{2*4}=\frac{-24}{8}
=-3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8}{2*4}=\frac{-8}{8}
=-1
$