(X+2)3+(x+2)=128

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Solution for (X+2)3+(x+2)=128 equation:


Simplifying
(X + 2) * 3 + (x + 2) = 128

Reorder the terms:
(2 + X) * 3 + (x + 2) = 128

Reorder the terms for easier multiplication:
3(2 + X) + (x + 2) = 128
(2 * 3 + X * 3) + (x + 2) = 128
(6 + 3X) + (x + 2) = 128

Reorder the terms:
6 + 3X + (2 + x) = 128

Remove parenthesis around (2 + x)
6 + 3X + 2 + x = 128

Reorder the terms:
6 + 2 + 3X + x = 128

Combine like terms: 6 + 2 = 8
8 + 3X + x = 128

Solving
8 + 3X + x = 128

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 3X + -8 + x = 128 + -8

Reorder the terms:
8 + -8 + 3X + x = 128 + -8

Combine like terms: 8 + -8 = 0
0 + 3X + x = 128 + -8
3X + x = 128 + -8

Combine like terms: 128 + -8 = 120
3X + x = 120

Add '-1x' to each side of the equation.
3X + x + -1x = 120 + -1x

Combine like terms: x + -1x = 0
3X + 0 = 120 + -1x
3X = 120 + -1x

Divide each side by '3'.
X = 40 + -0.3333333333x

Simplifying
X = 40 + -0.3333333333x

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