(X+2)/6=1-(x+4)/7

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Solution for (X+2)/6=1-(x+4)/7 equation: 



(X+2)/6=1-(X+4)/7

We move all terms to the left:

(X+2)/6-(1-(X+4)/7)=0

We calculate fractions


X/()+(-(1-(X+4)*6)/()=0



We calculate terms in parentheses: +(-(1-(X+4)*6)/(), so:

-(1-(X+4)*6)/(

We multiply all the terms by the denominator


-(1-(X+4)*6)



We calculate terms in parentheses: -(1-(X+4)*6), so:

1-(X+4)*6

determiningTheFunctionDomain
-(X+4)*6+1

We multiply parentheses

-6X-24+1

We add all the numbers together, and all the variables

-6X-23

Back to the equation:

-(-6X-23)



We get rid of parentheses

6X+23

Back to the equation:

+(6X+23)



We get rid of parentheses

X/()+6X+23=0

We multiply all the terms by the denominator


X+6X*()+23*()=0

We add all the numbers together, and all the variables

X+6X*()=0

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