(X+2)/6=(4-x)/4

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Solution for (X+2)/6=(4-x)/4 equation: 



(X+2)/6=(4-X)/4

We move all terms to the left:

(X+2)/6-((4-X)/4)=0

We add all the numbers together, and all the variables

(X+2)/6-((-1X+4)/4)=0

We calculate fractions


X/()+(-((-1X+4)*6)/()=0



We calculate terms in parentheses: +(-((-1X+4)*6)/(), so:

-((-1X+4)*6)/(

We multiply all the terms by the denominator


-((-1X+4)*6)



We calculate terms in parentheses: -((-1X+4)*6), so:

(-1X+4)*6

We multiply parentheses

-6X+24

Back to the equation:

-(-6X+24)



We get rid of parentheses

6X-24

Back to the equation:

+(6X-24)



We get rid of parentheses

X/()+6X-24=0

We multiply all the terms by the denominator


X+6X*()-24*()=0

We add all the numbers together, and all the variables

X+6X*()=0

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