(X+2)/(x+3)/(x*2-4)/(x-2)

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Solution for (X+2)/(x+3)/(x*2-4)/(x-2) equation: 


D( x )

x-2 = 0

x+3 = 0

2*x-4 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

2*x-4 = 0

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in (-oo:-3) U (-3:2) U (2:+oo)

(((X+2)/(x+3))/(2*x-4))/(x-2) = 0

(X+2)/((x+3)*(2*x-4)*(x-2)) = 0

x belongs to the empty set

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