(X+2)+x+(x-5)=48

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Solution for (X+2)+x+(x-5)=48 equation: 



(X+2)+X+(X-5)=48

We move all terms to the left:

(X+2)+X+(X-5)-(48)=0

We add all the numbers together, and all the variables

X+(X+2)+(X-5)-48=0

We get rid of parentheses

X+X+X+2-5-48=0

We add all the numbers together, and all the variables

3X-51=0

We move all terms containing X to the left, all other terms to the right

3X=51

X=51/3

X=17

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