(X+2)+(2x+1)+(3x-9)=36

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Solution for (X+2)+(2x+1)+(3x-9)=36 equation: 



(X+2)+(2X+1)+(3X-9)=36

We move all terms to the left:

(X+2)+(2X+1)+(3X-9)-(36)=0

We get rid of parentheses

X+2X+3X+2+1-9-36=0

We add all the numbers together, and all the variables

6X-42=0

We move all terms containing X to the left, all other terms to the right

6X=42

X=42/6

X=7

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