(X+2)(y+1)=22

Solution for (X+2)(y+1)=22 equation:

(X+2)(X+1)=22

We move all terms to the left:

(X+2)(X+1)-(22)=0

We multiply parentheses ..

(+X^2+X+2X+2)-22=0

We get rid of parentheses

X^2+X+2X+2-22=0

We add all the numbers together, and all the variables

X^2+3X-20=0

a = 1; b = 3; c = -20;
Δ = b2-4ac
Δ = 32-4·1·(-20)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*1}=\frac{-3-\sqrt{89}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*1}=\frac{-3+\sqrt{89}}{2}
$