(X+2)(x-6)=12

Solution for (X+2)(x-6)=12 equation:

(X+2)(X-6)=12

We move all terms to the left:

(X+2)(X-6)-(12)=0

We multiply parentheses ..

(+X^2-6X+2X-12)-12=0

We get rid of parentheses

X^2-6X+2X-12-12=0

We add all the numbers together, and all the variables

X^2-4X-24=0

a = 1; b = -4; c = -24;
Δ = b2-4ac
Δ = -42-4·1·(-24)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{7}}{2*1}=\frac{4-4\sqrt{7}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{7}}{2*1}=\frac{4+4\sqrt{7}}{2}
$