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(X+2)(X-3)=150
We move all terms to the left:
(X+2)(X-3)-(150)=0
We multiply parentheses ..
(+X^2-3X+2X-6)-150=0
We get rid of parentheses
X^2-3X+2X-6-150=0
We add all the numbers together, and all the variables
X^2-1X-156=0
a = 1; b = -1; c = -156;
Δ = b2-4ac
Δ = -12-4·1·(-156)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-25}{2*1}=\frac{-24}{2} =-12 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+25}{2*1}=\frac{26}{2} =13 $
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