(X+2)(x+5)-x(x+3)=26

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Solution for (X+2)(x+5)-x(x+3)=26 equation: 



(X+2)(X+5)-X(X+3)=26

We move all terms to the left:

(X+2)(X+5)-X(X+3)-(26)=0

We multiply parentheses

-X^2+(X+2)(X+5)-3X-26=0

We multiply parentheses ..

-X^2+(+X^2+5X+2X+10)-3X-26=0

We add all the numbers together, and all the variables

-1X^2+(+X^2+5X+2X+10)-3X-26=0

We get rid of parentheses

-1X^2+X^2+5X+2X-3X+10-26=0

We add all the numbers together, and all the variables

4X-16=0

We move all terms containing X to the left, all other terms to the right

4X=16

X=16/4

X=4

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