(X+2)(3x)=(x-3)2

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Solution for (X+2)(3x)=(x-3)2 equation: 



(X+2)(3X)=(X-3)2

We move all terms to the left:

(X+2)(3X)-((X-3)2)=0

We multiply parentheses

3X^2+6X-((X-3)2)=0



We calculate terms in parentheses: -((X-3)2), so:

(X-3)2

We multiply parentheses

2X-6

Back to the equation:

-(2X-6)



We get rid of parentheses

3X^2+6X-2X+6=0

We add all the numbers together, and all the variables

3X^2+4X+6=0

a = 3; b = 4; c = +6;
Δ = b2-4ac
Δ = 42-4·3·6
Δ = -56
Delta is less than zero, so there is no solution for the equation

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