(X+10)(x)=600

Solution for (X+10)(x)=600 equation:

(X+10)(X)=600

We move all terms to the left:

(X+10)(X)-(600)=0

We multiply parentheses

X^2+10X-600=0

a = 1; b = 10; c = -600;
Δ = b2-4ac
Δ = 102-4·1·(-600)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*1}=\frac{-60}{2}
=-30
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*1}=\frac{40}{2}
=20
$