(X+10)(3x-5)=180

Solution for (X+10)(3x-5)=180 equation:

(X+10)(3X-5)=180

We move all terms to the left:

(X+10)(3X-5)-(180)=0

We multiply parentheses ..

(+3X^2-5X+30X-50)-180=0

We get rid of parentheses

3X^2-5X+30X-50-180=0

We add all the numbers together, and all the variables

3X^2+25X-230=0

a = 3; b = 25; c = -230;
Δ = b2-4ac
Δ = 252-4·3·(-230)
Δ = 3385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{3385}}{2*3}=\frac{-25-\sqrt{3385}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{3385}}{2*3}=\frac{-25+\sqrt{3385}}{6}
$