(X+1)/5=(3x-1)/2

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Solution for (X+1)/5=(3x-1)/2 equation: 



(X+1)/5=(3X-1)/2

We move all terms to the left:

(X+1)/5-((3X-1)/2)=0

We calculate fractions


X/()+(-((3X-1)*5)/()=0



We calculate terms in parentheses: +(-((3X-1)*5)/(), so:

-((3X-1)*5)/(

We multiply all the terms by the denominator


-((3X-1)*5)



We calculate terms in parentheses: -((3X-1)*5), so:

(3X-1)*5

We multiply parentheses

15X-5

Back to the equation:

-(15X-5)



We get rid of parentheses

-15X+5

Back to the equation:

+(-15X+5)



We get rid of parentheses

X/()-15X+5=0

We multiply all the terms by the denominator


X-15X*()+5*()=0

We add all the numbers together, and all the variables

X-15X*()=0

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