(X+1)(x+1)=104

Solution for (X+1)(x+1)=104 equation:

(X+1)(X+1)=104

We move all terms to the left:

(X+1)(X+1)-(104)=0

We multiply parentheses ..

(+X^2+X+X+1)-104=0

We get rid of parentheses

X^2+X+X+1-104=0

We add all the numbers together, and all the variables

X^2+2X-103=0

a = 1; b = 2; c = -103;
Δ = b2-4ac
Δ = 22-4·1·(-103)
Δ = 416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{416}=\sqrt{16*26}=\sqrt{16}*\sqrt{26}=4\sqrt{26}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{26}}{2*1}=\frac{-2-4\sqrt{26}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{26}}{2*1}=\frac{-2+4\sqrt{26}}{2}
$