(X+1)(2x+1)=(x+3)(2x+3)+14

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Solution for (X+1)(2x+1)=(x+3)(2x+3)+14 equation: 



(X+1)(2X+1)=(X+3)(2X+3)+14

We move all terms to the left:

(X+1)(2X+1)-((X+3)(2X+3)+14)=0

We multiply parentheses ..

(+2X^2+X+2X+1)-((X+3)(2X+3)+14)=0



We calculate terms in parentheses: -((X+3)(2X+3)+14), so:

(X+3)(2X+3)+14

We multiply parentheses ..

(+2X^2+3X+6X+9)+14

We get rid of parentheses

2X^2+3X+6X+9+14

We add all the numbers together, and all the variables

2X^2+9X+23

Back to the equation:

-(2X^2+9X+23)



We get rid of parentheses

2X^2-2X^2+X+2X-9X+1-23=0

We add all the numbers together, and all the variables

-6X-22=0

We move all terms containing X to the left, all other terms to the right

-6X=22

X=22/-6

X=-3+2/3

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