(Q-5)x2=6

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Solution for (Q-5)x2=6 equation: 



(-5)Q2=6

We move all terms to the left:

(-5)Q2-(6)=0

We multiply parentheses

-5Q^2-6=0

a = -5; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·(-5)·(-6)
Δ = -120
Delta is less than zero, so there is no solution for the equation

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