(J-5)/2=(j+8)/7

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Solution for (J-5)/2=(j+8)/7 equation: 



(-5)/2=(J+8)/7

We move all terms to the left:

(-5)/2-((J+8)/7)=0

We calculate fractions


(-((J+8)*2)/()+()/()=0



We calculate terms in parentheses: +(-((J+8)*2)/()+()/(), so:

-((J+8)*2)/()+()/(

We add all the numbers together, and all the variables

-((J+8)*2)/()+1

We multiply all the terms by the denominator


-((J+8)*2)+1*()



We calculate terms in parentheses: -((J+8)*2), so:

(J+8)*2

We multiply parentheses

2J+16

Back to the equation:

-(2J+16)



We add all the numbers together, and all the variables

-(2J+16)

We get rid of parentheses

-2J-16

Back to the equation:

+(-2J-16)



We get rid of parentheses

-2J-16=0

We move all terms containing J to the left, all other terms to the right

-2J=16

J=16/-2

J=-8

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