(J+17+4)+(j+4)=49

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Solution for (J+17+4)+(j+4)=49 equation: 



(+17+4)+(J+4)=49

We move all terms to the left:

(+17+4)+(J+4)-(49)=0

determiningTheFunctionDomain
(J+4)-49+(+17+4)=0

We add all the numbers together, and all the variables

(J+4)-49+21=0

We add all the numbers together, and all the variables

(J+4)-28=0

We get rid of parentheses

J+4-28=0

We add all the numbers together, and all the variables

J-24=0

We move all terms containing J to the left, all other terms to the right

J=24

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