(F-G)(x)=(9x-6)-(3x+10)

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Solution for (F-G)(x)=(9x-6)-(3x+10) equation: 



(-)(F)=(9F-6)-(3F+10)

We move all terms to the left:

(-)(F)-((9F-6)-(3F+10))=0

We add all the numbers together, and all the variables

0F-((9F-6)-(3F+10))=0

We add all the numbers together, and all the variables

F-((9F-6)-(3F+10))=0



We calculate terms in parentheses: -((9F-6)-(3F+10)), so:

(9F-6)-(3F+10)

We get rid of parentheses

9F-3F-6-10

We add all the numbers together, and all the variables

6F-16

Back to the equation:

-(6F-16)



We get rid of parentheses

F-6F+16=0

We add all the numbers together, and all the variables

-5F+16=0

We move all terms containing F to the left, all other terms to the right

-5F=-16

F=-16/-5

F=3+1/5

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