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(3)(2E+3)(4E-8)=0
We multiply parentheses ..
3(+8E^2-16E+12E-24)=0
We multiply parentheses
24E^2-48E+36E-72=0
We add all the numbers together, and all the variables
24E^2-12E-72=0
a = 24; b = -12; c = -72;
Δ = b2-4ac
Δ = -122-4·24·(-72)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-84}{2*24}=\frac{-72}{48} =-1+1/2 $$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+84}{2*24}=\frac{96}{48} =2 $
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