(Cos(2x))(2cosx+1)=0

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Solution for (Cos(2x))(2cosx+1)=0 equation:


Simplifying
(Cos(2x))(2cosx + 1) = 0

Remove parenthesis around (2x)
(osC * 2x)(2cosx + 1) = 0

Reorder the terms for easier multiplication:
(2osC * x)(2cosx + 1) = 0

Multiply osC * x
(2osxC)(2cosx + 1) = 0

Remove parenthesis around (2osxC)
2osxC(2cosx + 1) = 0

Reorder the terms:
2osxC(1 + 2cosx) = 0
(1 * 2osxC + 2cosx * 2osxC) = 0

Reorder the terms:
(4co2s2x2C + 2osxC) = 0
(4co2s2x2C + 2osxC) = 0

Solving
4co2s2x2C + 2osxC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2osxC' to each side of the equation.
4co2s2x2C + 2osxC + -2osxC = 0 + -2osxC

Combine like terms: 2osxC + -2osxC = 0
4co2s2x2C + 0 = 0 + -2osxC
4co2s2x2C = 0 + -2osxC
Remove the zero:
4co2s2x2C = -2osxC

Divide each side by '4o2s2x2C'.
c = -0.5o-1s-1x-1

Simplifying
c = -0.5o-1s-1x-1

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