(C-2)(c+1)=0

Solution for (C-2)(c+1)=0 equation:

Simplifying
(C + -2)(c + 1) = 0

Reorder the terms:
(-2 + C)(c + 1) = 0

Reorder the terms:
(-2 + C)(1 + c) = 0

Multiply (-2 + C) * (1 + c)
(-2(1 + c) + C(1 + c)) = 0
((1 * -2 + c * -2) + C(1 + c)) = 0
((-2 + -2c) + C(1 + c)) = 0
(-2 + -2c + (1 * C + c * C)) = 0
(-2 + -2c + (1C + cC)) = 0

Reorder the terms:
(-2 + 1C + -2c + cC) = 0
(-2 + 1C + -2c + cC) = 0

Solving
-2 + 1C + -2c + cC = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 1C + -2c + 2 + cC = 0 + 2

Reorder the terms:
-2 + 2 + 1C + -2c + cC = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 1C + -2c + cC = 0 + 2
1C + -2c + cC = 0 + 2

Combine like terms: 0 + 2 = 2
1C + -2c + cC = 2

Add '2c' to each side of the equation.
1C + -2c + 2c + cC = 2 + 2c

Combine like terms: -2c + 2c = 0
1C + 0 + cC = 2 + 2c
1C + cC = 2 + 2c

Reorder the terms:
-2 + 1C + -2c + cC = 2 + 2c + -2 + -2c

Reorder the terms:
-2 + 1C + -2c + cC = 2 + -2 + 2c + -2c

Combine like terms: 2 + -2 = 0
-2 + 1C + -2c + cC = 0 + 2c + -2c
-2 + 1C + -2c + cC = 2c + -2c

Combine like terms: 2c + -2c = 0
-2 + 1C + -2c + cC = 0

The solution to this equation could not be determined.