(C+3)-2c-(5-3c)=2

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Solution for (C+3)-2c-(5-3c)=2 equation: 



(+3)-2C-(5-3C)=2

We move all terms to the left:

(+3)-2C-(5-3C)-(2)=0

determiningTheFunctionDomain
-2C-(5-3C)-2+(+3)=0

We add all the numbers together, and all the variables

-2C-(-3C+5)-2+3=0

We add all the numbers together, and all the variables

-2C-(-3C+5)+1=0

We get rid of parentheses

-2C+3C-5+1=0

We add all the numbers together, and all the variables

C-4=0

We move all terms containing C to the left, all other terms to the right

C=4

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