(C+13)-2c-(1-3c)=2

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Solution for (C+13)-2c-(1-3c)=2 equation: 



(+13)-2C-(1-3C)=2

We move all terms to the left:

(+13)-2C-(1-3C)-(2)=0

determiningTheFunctionDomain
-2C-(1-3C)-2+(+13)=0

We add all the numbers together, and all the variables

-2C-(-3C+1)-2+13=0

We add all the numbers together, and all the variables

-2C-(-3C+1)+11=0

We get rid of parentheses

-2C+3C-1+11=0

We add all the numbers together, and all the variables

C+10=0

We move all terms containing C to the left, all other terms to the right

C=-10

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