(B-2)(B-4)=

Solution for (B-2)(B-4)= equation:

Simplifying
(B + -2)(B + -4) = 0

Reorder the terms:
(-2 + B)(B + -4) = 0

Reorder the terms:
(-2 + B)(-4 + B) = 0

Multiply (-2 + B) * (-4 + B)
(-2(-4 + B) + B(-4 + B)) = 0
((-4 * -2 + B * -2) + B(-4 + B)) = 0
((8 + -2B) + B(-4 + B)) = 0
(8 + -2B + (-4 * B + B * B)) = 0
(8 + -2B + (-4B + B2)) = 0

Combine like terms: -2B + -4B = -6B
(8 + -6B + B2) = 0

Solving
8 + -6B + B2 = 0

Solving for variable 'B'.

Factor a trinomial.
(2 + -1B)(4 + -1B) = 0

Subproblem 1
Set the factor '(2 + -1B)' equal to zero and attempt to solve:

Simplifying
2 + -1B = 0

Solving
2 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1B = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1B = 0 + -2
-1B = 0 + -2

Combine like terms: 0 + -2 = -2
-1B = -2

Divide each side by '-1'.
B = 2

Simplifying
B = 2
Subproblem 2
Set the factor '(4 + -1B)' equal to zero and attempt to solve:

Simplifying
4 + -1B = 0

Solving
4 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1B = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1B = 0 + -4
-1B = 0 + -4

Combine like terms: 0 + -4 = -4
-1B = -4

Divide each side by '-1'.
B = 4

Simplifying
B = 4
Solution
B = {2, 4}