(A-7)/10=(a-2)/8

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Solution for (A-7)/10=(a-2)/8 equation: 



(-7)/10=(A-2)/8

We move all terms to the left:

(-7)/10-((A-2)/8)=0

We calculate fractions


(-((A-2)*10)/()+()/()=0



We calculate terms in parentheses: +(-((A-2)*10)/()+()/(), so:

-((A-2)*10)/()+()/(

We add all the numbers together, and all the variables

-((A-2)*10)/()+1

We multiply all the terms by the denominator


-((A-2)*10)+1*()



We calculate terms in parentheses: -((A-2)*10), so:

(A-2)*10

We multiply parentheses

10A-20

Back to the equation:

-(10A-20)



We add all the numbers together, and all the variables

-(10A-20)

We get rid of parentheses

-10A+20

Back to the equation:

+(-10A+20)



We get rid of parentheses

-10A+20=0

We move all terms containing A to the left, all other terms to the right

-10A=-20

A=-20/-10

A=+2

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