(A)2+(b)2=36

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Solution for (A)2+(b)2=36 equation: 



()2+(A)2=36

We move all terms to the left:

()2+(A)2-(36)=0

determiningTheFunctionDomain
A2-36+()2=0

We add all the numbers together, and all the variables

A^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$A=\frac{-b}{2a}=\frac{0}{2}=0$

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