(9x-77)=(12x-28)

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Solution for (9x-77)=(12x-28) equation: 



(9x-77)=(12x-28)

We move all terms to the left:

(9x-77)-((12x-28))=0

We get rid of parentheses

9x-((12x-28))-77=0



We calculate terms in parentheses: -((12x-28)), so:

(12x-28)

We get rid of parentheses

12x-28

Back to the equation:

-(12x-28)



We get rid of parentheses

9x-12x+28-77=0

We add all the numbers together, and all the variables

-3x-49=0

We move all terms containing x to the left, all other terms to the right

-3x=49

x=49/-3

x=-16+1/3

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