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(9x-6)=6(3x-2)+22
We move all terms to the left:
(9x-6)-(6(3x-2)+22)=0
We get rid of parentheses
9x-(6(3x-2)+22)-6=0
We calculate terms in parentheses: -(6(3x-2)+22), so:We get rid of parentheses
6(3x-2)+22
We multiply parentheses
18x-12+22
We add all the numbers together, and all the variables
18x+10
Back to the equation:
-(18x+10)
9x-18x-10-6=0
We add all the numbers together, and all the variables
-9x-16=0
We move all terms containing x to the left, all other terms to the right
-9x=16
x=16/-9
x=-1+7/9
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