(9x-6)+4x=(4x+12)

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Solution for (9x-6)+4x=(4x+12) equation: 



(9x-6)+4x=(4x+12)

We move all terms to the left:

(9x-6)+4x-((4x+12))=0

We add all the numbers together, and all the variables

4x+(9x-6)-((4x+12))=0

We get rid of parentheses

4x+9x-((4x+12))-6=0



We calculate terms in parentheses: -((4x+12)), so:

(4x+12)

We get rid of parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

13x-(4x+12)-6=0

We get rid of parentheses

13x-4x-12-6=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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