(9x-6)(8x+8)=0

Solution for (9x-6)(8x+8)=0 equation:

(9x-6)(8x+8)=0

We multiply parentheses ..

(+72x^2+72x-48x-48)=0

We get rid of parentheses

72x^2+72x-48x-48=0

We add all the numbers together, and all the variables

72x^2+24x-48=0

a = 72; b = 24; c = -48;
Δ = b2-4ac
Δ = 242-4·72·(-48)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-120}{2*72}=\frac{-144}{144}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+120}{2*72}=\frac{96}{144}
=2/3
$