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(9x-5)=(6x+20)
We move all terms to the left:
(9x-5)-((6x+20))=0
We get rid of parentheses
9x-((6x+20))-5=0
We calculate terms in parentheses: -((6x+20)), so:We get rid of parentheses
(6x+20)
We get rid of parentheses
6x+20
Back to the equation:
-(6x+20)
9x-6x-20-5=0
We add all the numbers together, and all the variables
3x-25=0
We move all terms containing x to the left, all other terms to the right
3x=25
x=25/3
x=8+1/3
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