(9x-5)(9x+5)=0

Solution for (9x-5)(9x+5)=0 equation:

(9x-5)(9x+5)=0

We use the square of the difference formula

81x^2-25=0

a = 81; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·81·(-25)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*81}=\frac{-90}{162}
=-5/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*81}=\frac{90}{162}
=5/9
$