(9x-5)(1-x)=0

Solution for (9x-5)(1-x)=0 equation:

(9x-5)(1-x)=0

We add all the numbers together, and all the variables

(9x-5)(-1x+1)=0

We multiply parentheses ..

(-9x^2+9x+5x-5)=0

We get rid of parentheses

-9x^2+9x+5x-5=0

We add all the numbers together, and all the variables

-9x^2+14x-5=0

a = -9; b = 14; c = -5;
Δ = b2-4ac
Δ = 142-4·(-9)·(-5)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*-9}=\frac{-18}{-18}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*-9}=\frac{-10}{-18}
=5/9
$