(9x-43)=(3x+29)

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Solution for (9x-43)=(3x+29) equation: 



(9x-43)=(3x+29)

We move all terms to the left:

(9x-43)-((3x+29))=0

We get rid of parentheses

9x-((3x+29))-43=0



We calculate terms in parentheses: -((3x+29)), so:

(3x+29)

We get rid of parentheses

3x+29

Back to the equation:

-(3x+29)



We get rid of parentheses

9x-3x-29-43=0

We add all the numbers together, and all the variables

6x-72=0

We move all terms containing x to the left, all other terms to the right

6x=72

x=72/6

x=12

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