(9x-4)/2=(4x+3)/7

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Solution for (9x-4)/2=(4x+3)/7 equation: 



(9x-4)/2=(4x+3)/7

We move all terms to the left:

(9x-4)/2-((4x+3)/7)=0

We calculate fractions


9x/()+(-((4x+3)*2)/()=0



We calculate terms in parentheses: +(-((4x+3)*2)/(), so:

-((4x+3)*2)/(

We multiply all the terms by the denominator


-((4x+3)*2)



We calculate terms in parentheses: -((4x+3)*2), so:

(4x+3)*2

We multiply parentheses

8x+6

Back to the equation:

-(8x+6)



We get rid of parentheses

-8x-6

Back to the equation:

+(-8x-6)



We get rid of parentheses

9x/()-8x-6=0

We multiply all the terms by the denominator


9x-8x*()-6*()=0

We add all the numbers together, and all the variables

9x-8x*()=0

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