(9x-4)(4x)=

Solution for (9x-4)(4x)= equation:

(9x-4)(4x)=

We move all terms to the left:

(9x-4)(4x)-()=0

We add all the numbers together, and all the variables

(9x-4)4x=0

We multiply parentheses

36x^2-16x=0

a = 36; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·36·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*36}=\frac{0}{72}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*36}=\frac{32}{72}
=4/9
$