(9x-3)/9=(5x-5)/3

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Solution for (9x-3)/9=(5x-5)/3 equation: 



(9x-3)/9=(5x-5)/3

We move all terms to the left:

(9x-3)/9-((5x-5)/3)=0

We calculate fractions


9x/()+(-((5x-5)*9)/()=0



We calculate terms in parentheses: +(-((5x-5)*9)/(), so:

-((5x-5)*9)/(

We multiply all the terms by the denominator


-((5x-5)*9)



We calculate terms in parentheses: -((5x-5)*9), so:

(5x-5)*9

We multiply parentheses

45x-45

Back to the equation:

-(45x-45)



We get rid of parentheses

-45x+45

Back to the equation:

+(-45x+45)



We get rid of parentheses

9x/()-45x+45=0

We multiply all the terms by the denominator


9x-45x*()+45*()=0

We add all the numbers together, and all the variables

9x-45x*()=0

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