(9x-27)/(2x-1)-(7)/(x-3)=2

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Solution for (9x-27)/(2x-1)-(7)/(x-3)=2 equation: 



(9x-27)/(2x-1)-(7)/(x-3)=2

We move all terms to the left:

(9x-27)/(2x-1)-(7)/(x-3)-(2)=0



Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R





Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



We calculate fractions


((9x-27)*(x-3))/((2x-1)*(x-3))+(-14x+7)/((2x-1)*(x-3))-2=0



We calculate terms in parentheses: +((9x-27)*(x-3))/((2x-1)*(x-3)), so:

(9x-27)*(x-3))/((2x-1)*(x-3)

We multiply all the terms by the denominator


(9x-27)*(x-3))

Back to the equation:

+((9x-27)*(x-3)))





We calculate terms in parentheses: +(-14x+7)/((2x-1)*(x-3)), so:

-14x+7)/((2x-1)*(x-3)

We multiply all the terms by the denominator


-14x*((2x-1)*(x-3)+7)

Back to the equation:

+(-14x*((2x-1)*(x-3)+7))

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