(9x-26)=(4x+43)+(2x-12)

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Solution for (9x-26)=(4x+43)+(2x-12) equation: 



(9x-26)=(4x+43)+(2x-12)

We move all terms to the left:

(9x-26)-((4x+43)+(2x-12))=0

We get rid of parentheses

9x-((4x+43)+(2x-12))-26=0



We calculate terms in parentheses: -((4x+43)+(2x-12)), so:

(4x+43)+(2x-12)

We get rid of parentheses

4x+2x+43-12

We add all the numbers together, and all the variables

6x+31

Back to the equation:

-(6x+31)



We get rid of parentheses

9x-6x-31-26=0

We add all the numbers together, and all the variables

3x-57=0

We move all terms containing x to the left, all other terms to the right

3x=57

x=57/3

x=19

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