(9x-26)=(2x-12)+(4x+43)

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Solution for (9x-26)=(2x-12)+(4x+43) equation: 



(9x-26)=(2x-12)+(4x+43)

We move all terms to the left:

(9x-26)-((2x-12)+(4x+43))=0

We get rid of parentheses

9x-((2x-12)+(4x+43))-26=0



We calculate terms in parentheses: -((2x-12)+(4x+43)), so:

(2x-12)+(4x+43)

We get rid of parentheses

2x+4x-12+43

We add all the numbers together, and all the variables

6x+31

Back to the equation:

-(6x+31)



We get rid of parentheses

9x-6x-31-26=0

We add all the numbers together, and all the variables

3x-57=0

We move all terms containing x to the left, all other terms to the right

3x=57

x=57/3

x=19

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